Home
Class 12
MATHS
The Cartesian equation of a line is (...

The Cartesian equation of a line is `(x-3)/2=(y+1)/(-2)=(z-3)/5` . Find the vector equation of the line.

Text Solution

Verified by Experts

The correct Answer is:
`r=3hat(i)-hat(j)+3hat(k)+lambda(2hat(i)-2hat(j)+5hat(k))`
Promotional Banner

Topper's Solved these Questions

  • THREE DIMENSIONAL COORDINATE SYSTEM

    ARIHANT MATHS|Exercise Exercise For Session 3|15 Videos
  • THREE DIMENSIONAL COORDINATE SYSTEM

    ARIHANT MATHS|Exercise Exercise For Session 4|7 Videos
  • THREE DIMENSIONAL COORDINATE SYSTEM

    ARIHANT MATHS|Exercise Exercise For Session 1|12 Videos
  • THEORY OF EQUATIONS

    ARIHANT MATHS|Exercise Exercise (Questions Asked In Previous 13 Years Exam)|35 Videos
  • TRIGONOMETRIC EQUATIONS AND INEQUATIONS

    ARIHANT MATHS|Exercise Exercise (Questions Asked In Previous 13 Years Exam)|12 Videos

Similar Questions

Explore conceptually related problems

The Cartesian equation of a line is (x+3)/2 = (y-5)/4 = (z+6)/2 . Find the vector equation for the line.

The cartesian equation of a line is (x-1)/(3)=(y-4)/(5)=(z-3)/(2) . Write its vector form.

If the cartesian equations of a line are : (3-x)/5=(y+4)/7=(2z-6)/4 , write the vector equation for the line.

The cartesian equation of a line is (x-5)/3 = (y+4)/7 = (z-6)/2 . Write its vector form.

The cartesian equation of a line is 6x - 2 = 3y + 1 = 2z - 2 . Find :(a) the direction-ratios of the line, and (b) vector equation of the line parallel to this line and· passing through the point (2, - 1, - 1).

Vector equation of the line (x+1)/(2)=(y-4)/(4)=(z+6)/(3)

The cartesian equations of a line are : (x-5)/3=(y+4)/7=(z-6)/2 and (x+3)/2=(y-5)/4=(z+6)/2 . find the vector equation of the lines.