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Given the equation of the line 3x-y+z+1=...

Given the equation of the line `3x-y+z+1=0 and 5x+y+3z=0`. Then,which of the following is correct?

A

Symmetrical form of the equation of line is `(x)/(2)=(y-(1)/(8))/(-1)=(z+(5)/(8))/(1)`.

B

Symmetrical form of the equation of line is `(x+(1)/(8))/(1)=(y-(5)/(8))/(-1)=(z)/(-2)`

C

Equation of the through `(2, 1, 4)` and perpencular to the given lines is `2x-y+z-7=0`.

D

Equation of the plane through `(2, 1, 4)` and perpendicular to the given lines is `x+y-2z+5=0`.

Text Solution

Verified by Experts

The correct Answer is:
(b, d)
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Knowledge Check

  • The planes 2x-y+3z-1=0 and 2x-y+3z+3=0 are

    A
    parallel
    B
    perpendicular
    C
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    parallel
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    None of these

  • The planes 2x-2y+4z+5=0 and 3x-3y+6z-1=0 are

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    parallel
    B
    perpendicular
    C
    Intersecting
    D
    None of these

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