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LCM of 3/5,6/25,9/5,12/15...

LCM of `3/5,6/25,9/5,12/15`

A

`12/5`

B

`12/25`

C

`36/25`

D

`36/5`

Text Solution

AI Generated Solution

The correct Answer is:
To find the LCM of the rational numbers \( \frac{3}{5}, \frac{6}{25}, \frac{9}{5}, \frac{12}{15} \), we will follow the rule that states: \[ \text{LCM of a rational number} = \frac{\text{LCM of the numerators}}{\text{HCF of the denominators}} \] ### Step 1: Identify the numerators and denominators The numerators are \( 3, 6, 9, 12 \) and the denominators are \( 5, 25, 5, 15 \). ### Step 2: Find the LCM of the numerators To find the LCM of \( 3, 6, 9, 12 \): - The prime factorization is: - \( 3 = 3^1 \) - \( 6 = 2^1 \times 3^1 \) - \( 9 = 3^2 \) - \( 12 = 2^2 \times 3^1 \) - The LCM is found by taking the highest power of each prime: - For \( 2 \): highest power is \( 2^2 \) from \( 12 \) - For \( 3 \): highest power is \( 3^2 \) from \( 9 \) Thus, the LCM is: \[ \text{LCM} = 2^2 \times 3^2 = 4 \times 9 = 36 \] ### Step 3: Find the HCF of the denominators To find the HCF of \( 5, 25, 5, 15 \): - The prime factorization is: - \( 5 = 5^1 \) - \( 25 = 5^2 \) - \( 15 = 3^1 \times 5^1 \) - The HCF is found by taking the lowest power of each prime: - For \( 5 \): lowest power is \( 5^1 \) - For \( 3 \): it does not appear in all, so we ignore it. Thus, the HCF is: \[ \text{HCF} = 5^1 = 5 \] ### Step 4: Calculate the LCM of the rational numbers Now, we can find the LCM of the rational numbers: \[ \text{LCM} = \frac{\text{LCM of the numerators}}{\text{HCF of the denominators}} = \frac{36}{5} \] ### Final Answer The LCM of \( \frac{3}{5}, \frac{6}{25}, \frac{9}{5}, \frac{12}{15} \) is: \[ \frac{36}{5} \] ---
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Knowledge Check

  • HCF of 6/5,3/25,9/15,12/5

    A
    `12/25`
    B
    `12/5`
    C
    `3/55`
    D
    `1/25`
  • Find the LCM of 15, 25, and 125.

    A
    5
    B
    125
    C
    300
    D
    375
  • LCM of 2.5,.075,.0015=

    A
    `.15`
    B
    `.075`
    C
    `.75`
    D
    `7.5`
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