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Number of stereoisomers possible for...

Number of stereoisomers possible for the octahedral complex `[Co(NH_3)_3 Cl_3]` and ` [Ni (en)_2 Cl_2 ]` respectively , are :
[en = 1,2 ethylenediamine ]

A

2 and 4

B

4 and 3

C

3 and 2

D

2 and 3

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The correct Answer is:
To determine the number of stereoisomers for the octahedral complexes \([Co(NH_3)_3Cl_3]\) and \([Ni(en)_2Cl_2]\), we will analyze each complex step by step. ### Step 1: Analyze the complex \([Co(NH_3)_3Cl_3]\) 1. **Identify the type of complex**: This complex has the formula MA3B3, where M is the metal (Co), A is the ligand (NH3), and B is the ligand (Cl). 2. **Determine the geometrical isomers**: For MA3B3 complexes, there are two possible geometrical isomers: - **Facial (fac)**: All three identical ligands (NH3) are on one face of the octahedron. - **Meridional (mer)**: The three identical ligands (NH3) are arranged in a plane that divides the octahedron into two equal halves. 3. **Count the stereoisomers**: - The fac isomer is optically inactive due to its symmetry. - The mer isomer is also optically inactive. - Therefore, there are **2 geometrical isomers** (fac and mer) for \([Co(NH_3)_3Cl_3]\). ### Step 2: Analyze the complex \([Ni(en)_2Cl_2]\) 1. **Identify the type of complex**: This complex has the formula MA2B2, where M is the metal (Ni), A is the ligand (en, ethylenediamine), and B is the ligand (Cl). 2. **Determine the geometrical isomers**: For MA2B2 complexes, there are two possible forms: - **Cis**: Both Cl ligands are adjacent to each other. - **Trans**: The Cl ligands are opposite each other. 3. **Count the stereoisomers**: - **Cis isomer**: This isomer lacks a plane of symmetry and can exist as two non-superimposable mirror images (enantiomers), making it optically active. Thus, it contributes **2 stereoisomers** (one for each enantiomer). - **Trans isomer**: This isomer has a plane of symmetry and is optically inactive, contributing **1 stereoisomer**. - Therefore, the total number of stereoisomers for \([Ni(en)_2Cl_2]\) is \(2 \text{ (from cis)} + 1 \text{ (from trans)} = 3\). ### Final Answer: - The number of stereoisomers for \([Co(NH_3)_3Cl_3]\) is **2**. - The number of stereoisomers for \([Ni(en)_2Cl_2]\) is **3**. ### Summary: - For \([Co(NH_3)_3Cl_3]\): 2 stereoisomers (fac and mer). - For \([Ni(en)_2Cl_2]\): 3 stereoisomers (2 from cis and 1 from trans).

To determine the number of stereoisomers for the octahedral complexes \([Co(NH_3)_3Cl_3]\) and \([Ni(en)_2Cl_2]\), we will analyze each complex step by step. ### Step 1: Analyze the complex \([Co(NH_3)_3Cl_3]\) 1. **Identify the type of complex**: This complex has the formula MA3B3, where M is the metal (Co), A is the ligand (NH3), and B is the ligand (Cl). 2. **Determine the geometrical isomers**: For MA3B3 complexes, there are two possible geometrical isomers: - **Facial (fac)**: All three identical ligands (NH3) are on one face of the octahedron. - **Meridional (mer)**: The three identical ligands (NH3) are arranged in a plane that divides the octahedron into two equal halves. ...
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Knowledge Check

  • Possible isomerism in complexes [Co(NH_3)_3 (NO_2)_3] and [Co(NH_3)_5 (NO_2)]Cl_2 , respectively are :

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