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The line Ax+By+C=0, cuts the circle x^(2...

The line `Ax+By+C=0`, cuts the circle `x^(2)+y^(2)+ax+by+c=0` in P and Q and the line `A'x+B'y+C'=0` cuts the circle `x^(2)+y^(2)+dx+b'y+c'=0` in R and S. If the four points P,Q,R,S are concyclic, then
`D=|(a-a',b-b',c-c'),(A,B,C),(A',B',C')|=0`

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Knowledge Check

  • The line ax+by+c=0 is normal to the circle x^(2)+y^(2)+2gy+2fy+d=0, if

    A
    ag+bf+c=0
    B
    ag+bf+-c=0
    C
    ag-bf+c=0
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    ag-bf-c=0
  • The line ax+by+c=0 is normal to the circle x^2+y^2+2gx+2fy+d=0 , if

    A
    ag+bf+c=0
    B
    ag+bf-c=0
    C
    ag-bf+c=0
    D
    ag-bf-c=0
  • The line ax +by+c=0 is an normal to the circle x^(2)+y^(2)=r^(2) . The portion of the line ax +by +c=0 intercepted by this circle is of length

    A
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    D
    2r
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