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For the curve x = t^2 - 1, y = t^2 - t, ...

For the curve `x = t^2 - 1, y = t^2 - t`, the tangent line is perpendicular to x-axis, where

A

`t=0`

B

`t=oo`

C

`t=1//sqrt3`

D

`t=1//sqrt3`

Text Solution

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The correct Answer is:
A
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Knowledge Check

  • For the curve x=t^(2)-1, y=t^(2)-t , the tangent is parallel to X-axis at the point where

    A
    `t=(1)/(sqrt3)`
    B
    `t=-(1)/(sqrt3)`
    C
    `t=0`
    D
    `t=(1)/(2)`

  • The point on the curve y= sqrt(x-1) where the tangent is perpendicular to the line 2x+y-5=0 is

    A
    `(2,-1)`
    B
    `(10,3)`
    C
    `(2,1)`
    D
    `(5,-2)`

  • The point on the curve y=sqrt(x-1) , where the tangent is perpendicular to the line 2x+y-5=0 is

    A
    (2,-1)
    B
    (10,3)
    C
    (2,1)
    D
    (5,-2)

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