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The equation of the parabloa whose fouce...

The equation of the parabloa whose fouce is thepoint `(2,3)` and directirix is the line `x-4y+3=0` is ....... and the lenght of its latus rectum is .....

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To find the equation of the parabola whose focus is at the point \( (2, 3) \) and whose directrix is the line \( x - 4y + 3 = 0 \), we can follow these steps: ### Step 1: Identify the Focus and Directrix The focus \( S \) of the parabola is given as \( (2, 3) \). The directrix is given by the equation \( x - 4y + 3 = 0 \). **Hint:** Remember that the focus is a point, while the directrix is a line. ### Step 2: Find the Equation of the Directrix We can rearrange the directrix equation to the slope-intercept form to better understand its position: \[ x - 4y + 3 = 0 \implies 4y = x + 3 \implies y = \frac{1}{4}x + \frac{3}{4} \] This shows that the directrix has a slope of \( \frac{1}{4} \). **Hint:** The directrix helps in determining the distance from any point on the parabola. ### Step 3: Use the Definition of a Parabola The definition of a parabola states that for any point \( P(x, y) \) on the parabola, the distance from \( P \) to the focus \( S \) is equal to the perpendicular distance from \( P \) to the directrix. ### Step 4: Calculate the Distance from \( P \) to the Focus The distance \( PS \) from point \( P(x, y) \) to the focus \( S(2, 3) \) is given by: \[ PS = \sqrt{(x - 2)^2 + (y - 3)^2} \] **Hint:** This is the Euclidean distance formula. ### Step 5: Calculate the Perpendicular Distance from \( P \) to the Directrix The perpendicular distance \( PM \) from point \( P(x, y) \) to the line \( x - 4y + 3 = 0 \) is given by: \[ PM = \frac{|x - 4y + 3|}{\sqrt{1^2 + (-4)^2}} = \frac{|x - 4y + 3|}{\sqrt{17}} \] **Hint:** The formula for the distance from a point to a line can be used here. ### Step 6: Set the Distances Equal According to the definition of a parabola: \[ \sqrt{(x - 2)^2 + (y - 3)^2} = \frac{|x - 4y + 3|}{\sqrt{17}} \] ### Step 7: Square Both Sides Squaring both sides gives: \[ (x - 2)^2 + (y - 3)^2 = \frac{(x - 4y + 3)^2}{17} \] ### Step 8: Clear the Denominator Multiply through by 17: \[ 17((x - 2)^2 + (y - 3)^2) = (x - 4y + 3)^2 \] ### Step 9: Expand Both Sides Expanding both sides: \[ 17((x^2 - 4x + 4) + (y^2 - 6y + 9)) = (x^2 - 8xy + 16y^2 + 6x - 24y + 9) \] This simplifies to: \[ 17x^2 - 68x + 153 + 17y^2 - 102y = x^2 - 8xy + 16y^2 + 6x - 24y + 9 \] ### Step 10: Rearrange to Form the Parabola Equation Collect all terms on one side: \[ 16x^2 + 8xy + y^2 - 74x - 78y + 144 = 0 \] ### Step 11: Find the Length of the Latus Rectum The length of the latus rectum \( L \) is given by the formula: \[ L = \frac{2p}{\sqrt{1 + m^2}} \] where \( p \) is the distance from the focus to the directrix. The distance from the focus \( (2, 3) \) to the line \( x - 4y + 3 = 0 \) can be calculated as: \[ PM = \frac{|2 - 4(3) + 3|}{\sqrt{17}} = \frac{|2 - 12 + 3|}{\sqrt{17}} = \frac{14}{\sqrt{17}} \] Thus, the length of the latus rectum is: \[ L = 2 \times \frac{14}{\sqrt{17}} = \frac{28}{\sqrt{17}} \] ### Final Answers 1. The equation of the parabola is: \[ 16x^2 + 8xy + y^2 - 74x - 78y + 144 = 0 \] 2. The length of the latus rectum is: \[ \frac{28}{\sqrt{17}} \]
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