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The value of sin"" ( pi )/(7 ) +sin"" ( ...

The value of `sin"" ( pi )/(7 ) +sin"" ( 2pi )/( 7 ) + sin "" ( 3pi )/(7)` is

A

`cot "" ( pi )/(14)`

B

`(1)/( 2) cot "" ( pi )/( 14)`

C

`tan "" ( pi )/( 14)`

D

`(1)/( 2) tan "" ( pi )/( 14)`

Text Solution

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The correct Answer is:
To find the value of \( \sin\left(\frac{\pi}{7}\right) + \sin\left(\frac{2\pi}{7}\right) + \sin\left(\frac{3\pi}{7}\right) \), we can use the sine addition formulas and properties of trigonometric functions. ### Step-by-Step Solution: 1. **Use the Sine Addition Formula**: We can group the terms and use the sine addition formula: \[ \sin A + \sin B = 2 \sin\left(\frac{A+B}{2}\right) \cos\left(\frac{A-B}{2}\right) \] Let's first combine \( \sin\left(\frac{\pi}{7}\right) \) and \( \sin\left(\frac{3\pi}{7}\right) \): \[ \sin\left(\frac{\pi}{7}\right) + \sin\left(\frac{3\pi}{7}\right) = 2 \sin\left(\frac{\frac{\pi}{7} + \frac{3\pi}{7}}{2}\right) \cos\left(\frac{\frac{\pi}{7} - \frac{3\pi}{7}}{2}\right) \] This simplifies to: \[ 2 \sin\left(\frac{2\pi}{7}\right) \cos\left(\frac{-\pi}{7}\right) = 2 \sin\left(\frac{2\pi}{7}\right) \cos\left(\frac{\pi}{7}\right) \] 2. **Combine with the Remaining Term**: Now, we have: \[ \sin\left(\frac{\pi}{7}\right) + \sin\left(\frac{2\pi}{7}\right) + \sin\left(\frac{3\pi}{7}\right) = 2 \sin\left(\frac{2\pi}{7}\right) \cos\left(\frac{\pi}{7}\right) + \sin\left(\frac{2\pi}{7}\right) \] Factor out \( \sin\left(\frac{2\pi}{7}\right) \): \[ = \sin\left(\frac{2\pi}{7}\right) \left(2 \cos\left(\frac{\pi}{7}\right) + 1\right) \] 3. **Evaluate the Expression**: We can now evaluate \( 2 \cos\left(\frac{\pi}{7}\right) + 1 \). We will use the known values of cosine for specific angles, but for this problem, we will keep it in this form. 4. **Final Expression**: The final expression for the sum is: \[ \sin\left(\frac{2\pi}{7}\right) \left(2 \cos\left(\frac{\pi}{7}\right) + 1\right) \] 5. **Conclusion**: The value of \( \sin\left(\frac{\pi}{7}\right) + \sin\left(\frac{2\pi}{7}\right) + \sin\left(\frac{3\pi}{7}\right) \) simplifies to: \[ \frac{1}{2} \cot\left(\frac{\pi}{14}\right) \]
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Knowledge Check

  • The value of sin"" (pi )/( 18) sin"" ( 5pi )/(18) sin"" ( 7pi )/( 18) is

    A
    `1//2`
    B
    `1//4`
    C
    `1//8`
    D
    `1//16`
  • The value of sum _(k = 1)^(6) ( sin "" ( 2 pi k)/( 7) - i cos "" ( 2 pi k)/( 7)) is

    A
    `-1`
    B
    0
    C
    `-i`
    D
    i
  • The value of sum_(k = 1)^(6) (sin "" ( 2 pi k)/( 7) - i cos "" ( 2 pi k)/( 7) ) is

    A
    i
    B
    `-1`
    C
    `-i`
    D
    0
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    The value of sin ""(pi)/(16) sin ""(3pi)/(16) sin ""(5pi)/(16) sin ""(7pi)/(16) is

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    To find the sum sin^(2) ""(2pi)/(7) + sin^(2)""(4pi)/(7) +sin^(2)""(8pi)/(7) , we follow the following method. Put 7theta = 2npi , where n is any integer. Then " " sin 4 theta = sin( 2npi - 3theta) = - sin 3theta This means that sin theta takes the values 0, pm sin (2pi//7), pmsin(2pi//7), pm sin(4pi//7), and pm sin (8pi//7) . From Eq. (i), we now get " " 2 sin 2 theta cos 2theta = 4 sin^(3) theta - 3 sin theta or 4 sin theta cos theta (1-2 sin^(2) theta)= sin theta ( 4sin ^(2) theta -3) Rejecting the value sin theta =0 , we get " " 4 cos theta (1-2 sin^(2) theta ) = 4 sin ^(2) theta - 3 or 16 cos^(2) theta (1-2 sin^(2) theta)^(2) = ( 4sin ^(2) theta -3)^(2) or 16(1-sin^(2) theta) (1-4 sin^(2) theta + 4 sin ^(4) theta) " " = 16 sin ^(4) theta - 24 sin ^(2) theta +9 or " " 64 sin^(6) theta - 112 sin^(4) theta - 56 sin^(2) theta -7 =0 This is cubic in sin^(2) theta with the roots sin^(2)( 2pi//7), sin^(2) (4pi//7), and sin^(2)(8pi//7) . The sum of these roots is " " sin^(2)""(2pi)/(7) + sin^(2)""(4pi)/(7) + sin ^(2)""(8pi)/(7) = (112)/(64) = (7)/(4) . The value of (tan^(2)""(pi)/(7) + tan^(2)""(2pi)/(7) + tan^(2)""(3pi)/(7))xx (cot^(2)""(pi)/(7) + cot^(2)""(2pi)/(7) + cot^(2)""(3pi)/(7)) is

    To find the sum sin^(2) ""(2pi)/(7) + sin^(2)""(4pi)/(7) +sin^(2)""(8pi)/(7) , we follow the following method. Put 7theta = 2npi , where n is any integer. Then " " sin 4 theta = sin( 2npi - 3theta) = - sin 3theta This means that sin theta takes the values 0, pm sin (2pi//7), pmsin(2pi//7), pm sin(4pi//7), and pm sin (8pi//7) . From Eq. (i), we now get " " 2 sin 2 theta cos 2theta = 4 sin^(3) theta - 3 sin theta or 4 sin theta cos theta (1-2 sin^(2) theta)= sin theta ( 4sin ^(2) theta -3) Rejecting the value sin theta =0 , we get " " 4 cos theta (1-2 sin^(2) theta ) = 4 sin ^(2) theta - 3 or 16 cos^(2) theta (1-2 sin^(2) theta)^(2) = ( 4sin ^(2) theta -3)^(2) or 16(1-sin^(2) theta) (1-4 sin^(2) theta + 4 sin ^(4) theta) " " = 16 sin ^(4) theta - 24 sin ^(2) theta +9 or " " 64 sin^(6) theta - 112 sin^(4) theta - 56 sin^(2) theta -7 =0 This is cubic in sin^(2) theta with the roots sin^(2)( 2pi//7), sin^(2) (4pi//7), and sin^(2)(8pi//7) . The sum of these roots is " " sin^(2)""(2pi)/(7) + sin^(2)""(4pi)/(7) + sin ^(2)""(8pi)/(7) = (112)/(64) = (7)/(4) . The value of tan^(2)""(pi)/(7)tan ^(2)""(2pi)/(7) tan ^(2)""(3pi)/(7) is

    sin""(pi)/(14)sin"" ( 3pi )/( 14)sin"" ( 5pi)/( 14)sin"" ( 7pi)/(14)