Discuss the shape of `SF_4`?

Explanation

Ground state electronic configuration of S(Z=16) is as follows :
S(Z=16) : `1s^2 2s^2 2p^6 3s^2 3p^4`
S(ground state) : `[Ne]^(10)`
S(excited state) : `[Ne]^(10) (##BCEP_APX_CHE_XII_C07_E01_092_S01.png" width="80%">
Lewis dot structure of `SF_4` indicates that the central atom ie, S has one lone pair and four bond pairs. Therefore on the basis of VSEPR theory has a see-saw geometry as shown below.

The hybridisation involved in `SF_4` is `sp^3 d`. Thus it has a trigonal bipyramidal structure in which one of the equatorial position is occupied by a lone pair of electrons: Thus molecular geometry of `SF_4` can be regarded as see-saw geometry .