Home
Class 11
CHEMISTRY
1.375 g of cupric oxide was reduced by h...

`1.375 g` of cupric oxide was reduced by heating in a current of hydrogen and the weight of copper that remained was `1.098 g` In another experiment, `1.179 g` of copper was dissolved in nitric acid and the resulting copper nitrate converted into cupric oxide by ignition. The weight of cupric oxide formed was `1.476 g`. Show that these result illustrate the law of constant composition.

Text Solution

Verified by Experts

`{:("Ist exp",,CuO=1.375gm),(,,Cu=1.098gm),(,,O=0.277gm),("IInd exp".,,Cu=1.179gm),(,,CuO=1.4476 gm),(,,O=0.2686gm):}`
`(Cu)/(O) = 3.9638=4 " "(Cu)/(O)=4`
In both the cases ratio of `Cu//O` is same
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • MOLE CONCEPT

    ALLEN|Exercise Exercise - 04[B]|27 Videos
  • MOLE CONCEPT

    ALLEN|Exercise Exercise - 05(A)|21 Videos
  • MOLE CONCEPT

    ALLEN|Exercise Comprehension # 9|4 Videos
  • IUPAC NOMENCLATURE

    ALLEN|Exercise Exercise - 05(B)|7 Videos
  • QUANTUM NUMBER & PERIODIC TABLE

    ALLEN|Exercise J-ADVANCED EXERCISE|24 Videos

Similar Questions

Explore conceptually related problems

2.75 g of cupric oxide was reduced by heating in a current of hydrogen and the weight of copper that remained was 2.196 g. Another experiment, 2.358 g of copper was dissolved in nitric acid and the resulting copper nitrate converted into cupric oxide by ignition. The weight of cupric oxide formed was 2.952 g. Show that these results illustrate law of constant composition.

2,75 g of cupric oxide was reduced by heating in a current of hydrogen and the weight of copper that remained was 2.196 g. Another experiment, 2.358 g of copper was dissolved in nitric acid and the resulting copper nitrate converted into cupric oxide by ignition. The weight of cupric oxide formed was 2.952 g. Show that these results illustrate law of constant composition.

1.80g of a certain metal burnt in oxygen gave 3.0g of its oxide 1.50g of the same metal heated in steam gave 2.50g of its oxide. Show that these illustrate the law of constant proportion .

Weight of copper oxide obtained by heating 2.16 g of metallic copper with HNO_(3) and subsequent ingnition was 2.70 g In another experient, 1.15 g of copper oxide on reduction yielded 0.92 g of copper. Show that the results illustrance the law of definite proportions.

In an experiment, 2.4 g of Iron oxide on reduction with Hydrogen yields 1.68 g of Iron. In another experiment, 2.9 g of Iron oxide give 2.03 g of Iron on reduction with Hydrogen. Show that the above data illustrates the law of constant proportion.

The same current if passed through solution of silver nitrate and cupric salt connected in series. If the weights of silver deposited is 1.08g . Calculate the weight of copper deposited

Copper oxide was prepared by two different methods. In case, 1.75 g of the metal gave 2. 19 g of oxide. In the second case, 1.14 g of the metal gave 1.43 g of the oxide, show that the given data illustrate the law of constant proportions.

Copper oxide was prepared by two different methods. In case, 1.75 g of the metal gave 2. 19 g of oxide. In the second case, 1.14 g of the metal gave 1.43 g of the oxide, show that the given data illustrate the law of constant proportions.

1.520 g of the hydroxide of a metal on ignition gave 0.995 g of oxide. The equivalent weight of metal is

1.40 g of a metal when heated in a current of oxygen gave 1.93 g of the metal oxide. Calculate the equivalent weight of the metal.