Home
Class 11
CHEMISTRY
A crystalline hydrated salt on being ren...

`A` crystalline hydrated salt on being rendered anhydrous, loses `45.6%` of its weight. The percentage composition of anhydrous salt is `:Al=10.5%, K=15.1%, S=24.8%` and `O=49.6%`. Find the empirical formula of the anhydrous and crystalline salt :

Text Solution

Verified by Experts

The correct Answer is:
`KAIS_(2)O_(8),KAIS_(2)O_(8).12H_(2)O`
Empirical formula
`KAlS_(2)O_(8){{:(Al,K,S,O,"Elements",),(10.5,15.1,24.8,49.6,"Mass percentage",),(0.388,0.387,0.775,3.1,"Mole ratio",),(1,1,2,8,"Simple ratio",):}`
Empirical formula weight `= 258`
From weight loss information `:54.4 g` anhydrous
salt `-= 45.6 g H_(2)O`
` implies 258g` anhydrous salt `-=216.26 g = 12` mol `H_(2)O`
implies Empirical formula of hydrated salt `=KAlS_(2)O_(8).12H_(2)O`
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • MOLE CONCEPT

    ALLEN|Exercise Exercise - 05(A)|21 Videos

  • MOLE CONCEPT

    ALLEN|Exercise Exercise - 05(B)|8 Videos

  • MOLE CONCEPT

    ALLEN|Exercise Exercise - 04 [A]|38 Videos

  • IUPAC NOMENCLATURE

    ALLEN|Exercise Exercise - 05(B)|7 Videos

  • QUANTUM NUMBER & PERIODIC TABLE

    ALLEN|Exercise J-ADVANCED EXERCISE|24 Videos

Similar Questions

Explore conceptually related problems

A crystalline salt on being rendered anhydrous loses 45.6% of its mass. The percentage composition of anhydrous salt is Al = 10.5%, K = 15.1 %, S = 24.8% and I = 49.6%. Calculate the simplest formula of anhydrous salt and the crystalline salt. (Al= 27, K = 39, S = 32, I= 127)

The percentage composition of a gas is : Nitrogen 82.35%, Hydrogen 17.64%. Find the empirical formula of the gas. [N = 14, H = 1]

Knowledge Check

  • An organic compound is found to contain C - 40%. 0 = 53.34% and H = 6.66%. Its empirical formula is

    A
    `CHO`
    B
    `CH_2 O `
    C
    `C_2 H_2 O`
    D
    `CH_4 O_2`

    • Similar Questions

    Explore conceptually related problems

    If the elemental composition of butyric acid is found to be 54.4% C, 9.13% H, and 36.5% O, determine the empirical formula.

    A compound contains C=40%,O=53.5% , and H=6.5% the empirical formula formula of the compound is:

    The crystalline salt Na_(2)SO_(4).xH_(2)O on heating loses 55.9 % of its weight. The formula of the crystalline salt is

    A crystalline compound when heated became anhydrous by losing 51.2 % of the mass. On analysis, the anhydrous compound gave the following percentage composition: Mg = 20.0 %, S = 26.66 % and O = 53.33 %, Calculate the molecular formula of the anhydrous compound and crystalline compound. The molecular mass of anhydrous compound is 120 u.

    Calculate the percentage composition of hydrated calcium chloride, CaCl_(2).6H_(2)O .

    A compound on analysis was found to contain C = 34.6 %, H = 3.85 % and O = 61.55% .Calculate its empirical formula.

    A compound has the following percentage composition by mass: carbon 14.4%, hydrogen 1.2% and chlorine 84.5%. Determine the empirical formula of this compound. Work correct to 1 decimal place. (H = 1, C = 12, CI = 35.5)

    Home
    Profile