The resistance of a `N//10 KCI` solution is 245 ohms. Calculate the specific conductance and the equivalent conductance of the solution if the electrodes in the cell are 4 cm apart and each having an area of 7.0 sq cm.

Answer

`2.332 xx 10^(-3) mho cm^(-1), 23.32 mho cm^(2) eq^(-1)`

Explanation

Cell constant `= (1)/(a) =(4)/(7) cm^(-1)`
specific conductance = conductance x cell constant
`=(1)/("resistance")xx(1)/(a)=(1)/(245)xx(4)/(7)=2.332 xx 10^(-3)"mhocm"^(-1)`
equivalent conductance = sp. Cond. `xx` volume ("cc") (containing 1 eq. of the substance)
`=2.332 xx 10^(-3) xx 10000` (for `N//10` solution,`V = 10,000 "cc"`)=`23.32 "mho cm"^(2)`.