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The equation of motion of a particle of ...

The equation of motion of a particle of mass `1g` is `(d^(2)x)/(dt^(2)) + pi^(2)x = 0`, where `x` is displacement (in m) from mean position. The frequency of oscillation is (in Hz)

A

`1/2`

B

`2`

C

`5sqrt(10)`

D

`(1)/(5sqrt(10))`

Text Solution

Verified by Experts

The correct Answer is:
A
`omega^(2) = pi^(2) rArr omega = pi = f = (omega)/(2pi) = (1)/(2)Hz`
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  • A particle moves such that its accleration a is given by a = -bx , where x is the displacement from equilibrium position and b is a constant. The period of oscillation is

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