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A mass M is performing linear simple har...

A mass M is performing linear simple harmonic motion. Then correct graph for acceleration a and corresponding linear velocity v is

A

B

C

D

Text Solution

Verified by Experts

The correct Answer is:
B
`v = A omegacos omegat, a = -omega^(2)A sin omegat`
`rArr ((v)/(Aomega))^(2) +((a)/(omega^(2) A))^(2) = 1`
`rArr` Straight line in `v^(2)` and `a^(2)`
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