Home
Class 12
CHEMISTRY
The oxidation number of phosphorus in PH...

The oxidation number of phosphorus in `PH_(4)^(+),PO_(2)^(3-),PO_(4)^(3-) and PO_(3)^(3-)` are respectively :-

A

`-3,+1,+3,+5`

B

`-3,+3,+5,+1`

C

`+3,-3,+5,+1`

D

`-3,+1,+5,+3`

Text Solution

AI Generated Solution

The correct Answer is:
To find the oxidation number of phosphorus in the compounds \( PH_4^+, PO_2^{3-}, PO_4^{3-}, \) and \( PO_3^{3-} \), we can follow these steps: ### Step 1: Determine the oxidation state in \( PH_4^+ \) 1. **Set up the equation**: Let the oxidation state of phosphorus be \( x \). 2. **Identify the oxidation states of hydrogen**: Hydrogen has an oxidation state of +1. 3. **Write the equation**: \[ x + 4(+1) = +1 \] 4. **Solve for \( x \)**: \[ x + 4 = +1 \\ x = +1 - 4 \\ x = -3 \] 5. **Conclusion**: The oxidation state of phosphorus in \( PH_4^+ \) is **-3**. ### Step 2: Determine the oxidation state in \( PO_2^{3-} \) 1. **Set up the equation**: Let the oxidation state of phosphorus be \( x \). 2. **Identify the oxidation states of oxygen**: Oxygen has an oxidation state of -2. 3. **Write the equation**: \[ x + 2(-2) = -3 \] 4. **Solve for \( x \)**: \[ x - 4 = -3 \\ x = -3 + 4 \\ x = +1 \] 5. **Conclusion**: The oxidation state of phosphorus in \( PO_2^{3-} \) is **+1**. ### Step 3: Determine the oxidation state in \( PO_4^{3-} \) 1. **Set up the equation**: Let the oxidation state of phosphorus be \( x \). 2. **Write the equation**: \[ x + 4(-2) = -3 \] 3. **Solve for \( x \)**: \[ x - 8 = -3 \\ x = -3 + 8 \\ x = +5 \] 4. **Conclusion**: The oxidation state of phosphorus in \( PO_4^{3-} \) is **+5**. ### Step 4: Determine the oxidation state in \( PO_3^{3-} \) 1. **Set up the equation**: Let the oxidation state of phosphorus be \( x \). 2. **Write the equation**: \[ x + 3(-2) = -3 \] 3. **Solve for \( x \)**: \[ x - 6 = -3 \\ x = -3 + 6 \\ x = +3 \] 4. **Conclusion**: The oxidation state of phosphorus in \( PO_3^{3-} \) is **+3**. ### Final Summary of Oxidation States - \( PH_4^+ \): -3 - \( PO_2^{3-} \): +1 - \( PO_4^{3-} \): +5 - \( PO_3^{3-} \): +3 Thus, the oxidation numbers of phosphorus in the respective compounds are **-3, +1, +5, +3**.
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • REDOX REACTIONS

    ALLEN|Exercise EXERICSE - 3|30 Videos
  • REDOX REACTIONS

    ALLEN|Exercise EXERICSE - 4|27 Videos
  • REDOX REACTIONS

    ALLEN|Exercise Exercise - 1|61 Videos
  • Redox Reaction

    ALLEN|Exercise All Questions|19 Videos
  • s-Block element

    ALLEN|Exercise All Questions|14 Videos

Similar Questions

Explore conceptually related problems

The oxidation number of phosphorus in PO_(4)^(3-), P_(4)O_(10) , and P_(2)O_(7)^(4-) is

What is the oxidation number of phosphorus in H_(3)PO_(4) molecule ?

Oxidation number of P in PO_(4)^(3-) , of S in SO_(4)^(2-) and that of Cr_(2)O_(7)^(2-) are respectively

Oxidation number of P in PO_(4)^(3-) , of S in SO_(4)^(2-) and that of Cr_(2)O_(7)^(2-) are respectively

What is the oxidation number of phosphorus in H_(3)PO_(2) molecule ?

The oxidation number of P in KH_(2)PO_(3) is ..........

The true statement of the acids of phosphorus H_(3)PO_(2),H_(3)PO_(3) and H__(3)PO_(4) is :

The true statement for the acids of phosphorus, H_(3)PO_(2), H_(3)PO_(3) and H_(3)PO_(4) is

State true or false : The geometry of phosphorus in H_(3)PO_(2),H_(3)PO_(3) and H_(3)PO_(4) is tetrahedral

Calculate the oxidation number of phosphorus in the following species. (a) HPO_(3)^(2-) " " (b) PO_(4)^(3-)