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A + B hArr C + D, Kc = 5 If at some tim...

` A + B hArr C + D, K_c = 5` If at some time the concentration of A, B, C and D are 1, 2, 3, 4M, then find out the direction of reaction at this time.

A

Forward

B

Backward

C

At equilibrium

D

Cannot be found

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The correct Answer is:
To determine the direction of the reaction given the equilibrium constant \( K_c \) and the concentrations of the reactants and products, we can follow these steps: ### Step 1: Write the expression for the equilibrium constant \( K_c \) For the reaction: \[ A + B \rightleftharpoons C + D \] The equilibrium constant \( K_c \) is given by the formula: \[ K_c = \frac{[C][D]}{[A][B]} \] ### Step 2: Substitute the known values into the \( K_c \) expression Given: - Concentration of \( A = 1 \, M \) - Concentration of \( B = 2 \, M \) - Concentration of \( C = 3 \, M \) - Concentration of \( D = 4 \, M \) We can substitute these values into the expression for \( Q_c \) (the reaction quotient): \[ Q_c = \frac{[C][D]}{[A][B]} = \frac{(3)(4)}{(1)(2)} \] ### Step 3: Calculate \( Q_c \) Now, we calculate \( Q_c \): \[ Q_c = \frac{12}{2} = 6 \] ### Step 4: Compare \( Q_c \) with \( K_c \) We know that: - \( K_c = 5 \) - \( Q_c = 6 \) Now we compare \( Q_c \) with \( K_c \): - Since \( Q_c (6) > K_c (5) \), the reaction will shift to the left (backward direction) to reach equilibrium. ### Conclusion The direction of the reaction at this time is backward. ---
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