`CH_(2)=C=CH-CH_(3),` total number of `sigma` & `pi` bonds in given compound will be :-

Options

A. `3,3`
B. `9,2`
C. `2,9`
D. `1,2`

Answer

To determine the total number of sigma (σ) and pi (π) bonds in the compound CH₂=C=CH-CH₃, we can follow these steps:

### Step 1: Identify the Structure
The compound CH₂=C=CH-CH₃ can be visualized as:
- CH₂ (with two hydrogen atoms attached to a carbon)
- C (double bonded to another carbon)
- C (double bonded to another carbon)
- CH₃ (with three hydrogen atoms attached to a carbon)

### Step 2: Count the Sigma Bonds
- **Single Bonds:** Each single bond is a sigma bond.
- **Double Bonds:** Each double bond consists of one sigma bond and one pi bond.

**Counting the sigma bonds:**
1. CH₂ to C (1 sigma bond)
2. C to C (1 sigma bond from the first double bond)
3. C to C (1 sigma bond from the second double bond)
4. C to CH₃ (1 sigma bond)
5. Each hydrogen attached to CH₂ (2 sigma bonds)
6. Each hydrogen attached to CH₃ (3 sigma bonds)

Now, let's count:
- From CH₂ to C: 1
- From C to C (first double bond): 1
- From C to C (second double bond): 1
- From C to CH₃: 1
- From CH₂ (2 H): 2
- From CH₃ (3 H): 3

Total sigma bonds = 1 + 1 + 1 + 1 + 2 + 3 = **9 sigma bonds**

### Step 3: Count the Pi Bonds
- Each double bond has one pi bond.
- In this compound, there are two double bonds.

Total pi bonds = 2 (one from each double bond)

### Conclusion
- Total number of sigma bonds = 9
- Total number of pi bonds = 2

Thus, the total number of sigma and pi bonds in the compound CH₂=C=CH-CH₃ is **9 sigma bonds and 2 pi bonds**.

### Final Answer
The total number of sigma and pi bonds in the compound is **9 sigma bonds and 2 pi bonds**.

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