Number of peroxide linkage in `CrO_(5), H_(2)SO_(5), H_(2)S_(2)O_(8)` are respectively :-

Options

A. 2, 1, 2
B. 2, 2, 2
C. 1, 1, 1
D. 2, 1, 1

Explanation

To find the number of peroxide linkages in the compounds CrO5, H2SO5, and H2S2O8, we will analyze each compound step by step.

### Step 1: Analyze CrO5
1. **Structure**: CrO5 has a unique structure known as the "butterfly structure." In this structure, there are five oxygen atoms surrounding a chromium atom.
2. **Peroxide Linkage**: A peroxide linkage is characterized by an O-O bond. In CrO5, there are two O-O linkages present.
3. **Conclusion for CrO5**: Therefore, the number of peroxide linkages in CrO5 is **2**.

### Step 2: Analyze H2SO5
1. **Structure**: H2SO5 can be represented with a sulfur atom bonded to two double-bonded oxygen atoms (O=O) and one peroxide linkage (O-OH).
2. **Peroxide Linkage**: In H2SO5, there is one O-O bond present, which is characteristic of a peroxide linkage.
3. **Conclusion for H2SO5**: Thus, the number of peroxide linkages in H2SO5 is **1**.

### Step 3: Analyze H2S2O8
1. **Structure**: H2S2O8 consists of two sulfur atoms. The structure can be drawn with each sulfur atom connected to double-bonded oxygen atoms and single-bonded oxygen atoms forming a peroxide linkage.
2. **Peroxide Linkage**: In H2S2O8, there is one O-O bond present, indicating one peroxide linkage.
3. **Conclusion for H2S2O8**: Therefore, the number of peroxide linkages in H2S2O8 is **1**.

### Final Summary
- **CrO5**: 2 peroxide linkages
- **H2SO5**: 1 peroxide linkage
- **H2S2O8**: 1 peroxide linkage

Thus, the final answer is:
**2, 1, 1** for CrO5, H2SO5, and H2S2O8 respectively.