In `S_(8)` each sulphur atom is :-

Options

A. sp hybridised with a planar ring
B. `sp^(3)` hybridised with a planar ring
C. `sp^(3)` hybridised with a non-planar ring
D. `sp^(3)d` hybridised two sulphur atoms

Answer

To determine the hybridization and geometry of each sulfur atom in \( S_8 \), we can follow these steps:

### Step 1: Understand the Structure of \( S_8 \)
The molecule \( S_8 \) consists of eight sulfur atoms arranged in a crown shape. This cyclic structure is important for determining the hybridization of the sulfur atoms.

### Step 2: Identify the Hybridization
In \( S_8 \), each sulfur atom forms two single covalent bonds with adjacent sulfur atoms. To accommodate these bonds, the sulfur atoms undergo hybridization.

### Step 3: Determine the Type of Hybridization
Sulfur has six valence electrons and needs to form two bonds in \( S_8 \). The hybridization that allows for the formation of two sigma bonds and accommodates the lone pairs is \( sp^3 \).

### Step 4: Analyze the Geometry
The arrangement of the sulfur atoms in \( S_8 \) is not planar; it forms a non-planar ring. This is due to the angle strain and the need to minimize repulsion between the lone pairs of electrons.

### Step 5: Conclusion
Thus, each sulfur atom in \( S_8 \) is \( sp^3 \) hybridized and is part of a non-planar ring structure.

### Final Answer
Each sulfur atom in \( S_8 \) is \( sp^3 \) hybridized with a non-planar ring.

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