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If A=[{:(1,2,2),(2,1,2),(2,2,1):}], find...

If `A=[{:(1,2,2),(2,1,2),(2,2,1):}]`, find `A^(-1)` and hence prove that `A^(2)-4A-5I=0`.

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The correct Answer is:
`(1)/(5)[{:(-3,2,2),(2,-3,2),(2,2,-3):}]`
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