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A solution contains 50 mL of alcohol ...

A solution contains 50 mL of alcohol mixed with 150 mL of water. Calculate the concentration of this solution .

Text Solution

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This solution contains a liquid solute (alcohol) mixed with a liquid solvent (water), so we have to calculate the concentration of this solution in terms of volume percentage of solute (alcohol). Now, we know that : Concentration of solution
`=("Volume of solute")/("VOlume of solution ")xx 100`
Here, Volume of solute (alcohol) = 50 mL
And, Volume of solvent (water) = 150 mL
So, Volume of solution =
Volume of solute + Volume of solvent = 50 + 150 = 200 mL
Now, putting the values of .volume of solute. and .volume of solution. in the above formula we get : Concentration of solution (v/v)
`=(50 )/(200) xx 100 = (50 )/(2) = 25 % `
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Knowledge Check

  • A 50.0 mL solution of 0.150 M HCl. Is mixed with 25.0 mL of 0.400 M HCl What is the HCI concentration in the final solution? (Assume volumes are additive.)

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