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{:("List-I","List-II"),((P)C(n)H(2n+2),(...

`{:("List-I","List-II"),((P)C_(n)H_(2n+2),(1)"Alkyne"),((Q) C_(n)H_(2n),(2)"Alkene"),((R ) C_(n)H_(2n-2),(3)"Alkane"),((S)C_(n)H_(2n-1),(4)"Alkyl group"):}`

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To solve the problem of matching the general formulas of hydrocarbons with their respective names, we can follow these steps: ### Step 1: Identify the General Formula for Alkanes - The general formula for alkanes is \( C_nH_{2n+2} \). - This means for every n carbon atoms, there are \( 2n + 2 \) hydrogen atoms. **Hint:** Remember that alkanes are saturated hydrocarbons with single bonds. ### Step 2: Identify the General Formula for Alkenes - The general formula for alkenes is \( C_nH_{2n} \). - This indicates that for every n carbon atoms, there are \( 2n \) hydrogen atoms. **Hint:** Alkenes contain at least one double bond between carbon atoms. ### Step 3: Identify the General Formula for Alkynes - The general formula for alkynes is \( C_nH_{2n-2} \). - This shows that for every n carbon atoms, there are \( 2n - 2 \) hydrogen atoms. **Hint:** Alkynes contain at least one triple bond between carbon atoms. ### Step 4: Identify the General Formula for Alkyl Groups - The general formula for alkyl groups is \( C_nH_{2n-1} \). - This means that for every n carbon atoms, there are \( 2n - 1 \) hydrogen atoms. **Hint:** Alkyl groups are derived from alkanes by removing one hydrogen atom. ### Step 5: Match Each Formula with Its Name - **P: \( C_nH_{2n+2} \)** matches with **(3) Alkane**. - **Q: \( C_nH_{2n} \)** matches with **(2) Alkene**. - **R: \( C_nH_{2n-2} \)** matches with **(1) Alkyne**. - **S: \( C_nH_{2n-1} \)** matches with **(4) Alkyl group**. ### Final Matching: - P → 3 (Alkane) - Q → 2 (Alkene) - R → 1 (Alkyne) - S → 4 (Alkyl group) ### Summary of Matches: - **P (C_nH_{2n+2})** → **(3) Alkane** - **Q (C_nH_{2n})** → **(2) Alkene** - **R (C_nH_{2n-2})** → **(1) Alkyne** - **S (C_nH_{2n-1})** → **(4) Alkyl group**
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Similar Questions

Explore conceptually related problems

C_(n)H_(2n)O_(2) is the formula of

Prove that `(""^(2n)C_(0))^2-(""^(2n)C_(1))^2+(""^(2n)C_(2))^2-.....+(-1)^n(""^(2n)C_(2n))^2=(-1)^n.""^(2n)C_(n)`

STATEMENT - 1 : If n is even, `.^(2n)C_(1)+.^(2n)C_(3)+.^(2n)C_(5)+"….."+.^(2n)C_(n-1) = 2^(2n-1)`.
STATEMENT - 2 : `.^(2n)C_(1) + .^(2n)C_(3)+ .^(2n)C_(5) + "……"+ .^(2n)C_(2n-1) = 2^(2n-1)`

Is an alkyl group represented by the general formula C_(n)H_(2n+1) ?

Prove that
`(""^(2n)C_(0))^(2)-(""^(2n)C_(1))^(2)+(""^(2n)C_(2))-(""^(2n)C_(3))^(2)+......+(""^(2n)C_(2n))^(2)=(-1)^(n)(""^(2n)C_(n))^2.`

सिद्ध कीजिए कि
`.^(2n)C_(n)+^(2n)C_(n-1) = 1/2*^(2n+2)C_(n+1)`

`C_(n)H_(2n-2)` का आई.यू.पी.ए.सी. नाम है

The formula C_(n)H_(2n-2) shows

`{:(1.,C_(n)H_(2n+2),(a),"Alkene"),(2.,C_(n)H_(2n),(b),"Alcohol"),(3.,C_(n)H_(2n-2),(c),"Alkane"),(4.,ROH,(d),"Alkyne"):}`

Which of the following formulae represents a saturated hydrocarbon?
`C_(n)H_(2n+2), C_(n)H_(2n+1), C_(n)H_(2n), C_(n)H_(2n-2)`

""^(2n)C_(0),""^(2n)C_(1),""^(2n)C_(2),…….,""^(2n)C_(n) (Where n is an even number)

Prove that, `C_(0) *""^(2n)C_(n)-C_(1)*""^((2n-2))C_(n)+C_(2) *""^((2n-4))C_(n)-…..=2^(n)`

सिद्ध कीजिये : `(""^(2n) C_(0))^(2)-(""^(2n)C_(1))^(2)+(""^(2n)C_(2))^(2)-……+(-1)^(n) (""^(2n)C_(2n))^(2)=(-1)^(n). ""^(2n)C_(n)`.

STATEMENT - 1 : If n is even, `.^(2n)C_(1)+.^(2n)C_(3)+.^(2n)C_(5)+"….."+.^(2n)C_(n-1) = 2^(2n-2)`.
STATEMENT - 2 : `.^(2n)C_(1) + .^(2n)C_(3)+ .^(2n)C_(5) + "……"+ .^(2n)C_(2n-1) = 2^(2n-1)`