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A compound contians 3 xx 10^(24) oxygen ...

A compound contians `3 xx 10^(24)` oxygen atoms. Number of moles of oxygen present in the sample is `"__________"`.

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To find the number of moles of oxygen present in a sample that contains \(3 \times 10^{24}\) oxygen atoms, we can follow these steps: ### Step 1: Understand the relationship between atoms and moles One mole of any substance contains \(6.022 \times 10^{23}\) entities (atoms, molecules, etc.). This number is known as Avogadro's number. ### Step 2: Set up the equation To find the number of moles (\(n\)) of oxygen, we can use the formula: \[ n = \frac{\text{Number of atoms}}{\text{Avogadro's number}} \] In this case, the number of atoms is \(3 \times 10^{24}\). ### Step 3: Substitute the values into the equation Substituting the values we have: \[ n = \frac{3 \times 10^{24}}{6.022 \times 10^{23}} \] ### Step 4: Perform the calculation Now we can perform the division: \[ n = \frac{3}{6.022} \times \frac{10^{24}}{10^{23}} = \frac{3}{6.022} \times 10^{1} \] Calculating \(\frac{3}{6.022} \approx 0.498\), we get: \[ n \approx 0.498 \times 10^{1} = 4.98 \] ### Step 5: Round the result Rounding \(4.98\) gives us approximately \(5\). ### Final Answer The number of moles of oxygen present in the sample is **5 moles**. ---

To find the number of moles of oxygen present in a sample that contains \(3 \times 10^{24}\) oxygen atoms, we can follow these steps: ### Step 1: Understand the relationship between atoms and moles One mole of any substance contains \(6.022 \times 10^{23}\) entities (atoms, molecules, etc.). This number is known as Avogadro's number. ### Step 2: Set up the equation To find the number of moles (\(n\)) of oxygen, we can use the formula: \[ ...
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Knowledge Check

  • 1.5 moles of oxygen atoms are present in

    A
    0.5 moles of `BaCO_(3)`
    B
    1 mole of `BaCO_(3)`
    C
    2 moles of `BaCO_(3)`
    D
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  • A sample of Ammonium phosphate (NH_(4))_(3)PO_(4) contains 3.18 moles of oxygen atoms. The number of moles of oxygen atom in the sample is

    A
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    B
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    C
    1.06
    D
    3.18
  • A sample of ammonium phosphate (NH_(4))_(3) PO_(4) contains 3.18 moles of hyrogen atoms . The number of moles of oxygen atoms in the sample is

    A
    `0.265`
    B
    `0.795`
    C
    `1.06`
    D
    `4.00`
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