PASSAGE-II : Empirical formula is the simplest formula of the compound which gives the atomic ratio of various elements present in one molecule of the compound. However, the molecular formula of the compound gives the number of atoms of various elements present in one molecule of the compound. Molacular formula = (Empirical formula) `xxn`
implies `n=("Molecular mass")/("Empirical formula mass")`
A compound may have same empirical and molecular formula. Both these formulae are calculated using percentage composition of constituent elements.
Which of the following compounds have the same empirical formula as that of formaldehyde?

Options

A. Formic acid
B. Glucose
C. Sucrose
D. Ethanol

Explanation

To determine which of the following compounds has the same empirical formula as that of formaldehyde (HCHO), we first need to identify the empirical formula of formaldehyde.

### Step 1: Identify the empirical formula of formaldehyde
- The molecular formula of formaldehyde is HCHO.
- To find the empirical formula, we look for the simplest whole number ratio of the elements in the compound.
- In HCHO, we have:
- Hydrogen (H): 2 atoms
- Carbon (C): 1 atom
- Oxygen (O): 1 atom
- The simplest ratio of H:C:O is 2:1:1.
- Therefore, the empirical formula of formaldehyde is CH₂O.

### Step 2: Check the empirical formulas of the given compounds
Now, we will check the empirical formulas of the provided compounds to see which one matches CH₂O.

1. **Formic Acid (HCOOH)**:
- Molecular formula: HCOOH
- Simplifying HCOOH gives us:
- H: 2
- C: 1
- O: 2
- The empirical formula is CH₂O.

2. **Glucose (C₆H₁₂O₆)**:
- Molecular formula: C₆H₁₂O₆
- Simplifying C₆H₁₂O₆ gives us:
- H: 12 / 6 = 2
- C: 6 / 6 = 1
- O: 6 / 6 = 1
- The empirical formula is CH₂O.

3. **Sucrose (C₁₂H₂₂O₁₁)**:
- Molecular formula: C₁₂H₂₂O₁₁
- Simplifying C₁₂H₂₂O₁₁ gives us:
- H: 22 / 11 = 2
- C: 12 / 12 = 1
- O: 11 / 11 = 1
- The empirical formula is C₁H₁.

4. **Ethanol (C₂H₅OH)**:
- Molecular formula: C₂H₅OH
- Simplifying C₂H₅OH gives us:
- H: 6 / 2 = 3
- C: 2 / 2 = 1
- O: 1 / 1 = 1
- The empirical formula is C₂H₅O.

### Step 3: Conclusion
The compounds that have the same empirical formula as formaldehyde (CH₂O) are:
- Formic Acid (HCOOH) → CH₂O
- Glucose (C₆H₁₂O₆) → CH₂O

### Final Answer
The compounds that have the same empirical formula as that of formaldehyde are **Formic Acid and Glucose**.

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