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Molecular formula of acetic acid is CH(3...

Molecular formula of acetic acid is `CH_(3)COOH`. The number of atoms present in its empirical formula is

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To find the number of atoms present in the empirical formula of acetic acid (CH₃COOH), we will follow these steps: ### Step 1: Identify the Molecular Formula The molecular formula of acetic acid is given as CH₃COOH. ### Step 2: Count the Atoms in the Molecular Formula In the molecular formula CH₃COOH, we can count the number of each type of atom: - Carbon (C): 2 atoms (from CH₃ and COOH) - Hydrogen (H): 4 atoms (3 from CH₃ and 1 from COOH) - Oxygen (O): 2 atoms (from COOH) ### Step 3: Write the Total Count Now, we can summarize the total count of atoms: - Total Carbon atoms = 2 - Total Hydrogen atoms = 4 - Total Oxygen atoms = 2 ### Step 4: Determine the Empirical Formula To find the empirical formula, we need to express the ratio of the atoms in the simplest form. The counts we have are: - C: 2 - H: 4 - O: 2 Now we will divide each count by the smallest number of atoms present, which is 2: - C: 2/2 = 1 - H: 4/2 = 2 - O: 2/2 = 1 This gives us the empirical formula: CH₂O. ### Step 5: Count the Atoms in the Empirical Formula Now, let's count the number of atoms in the empirical formula CH₂O: - Carbon (C): 1 atom - Hydrogen (H): 2 atoms - Oxygen (O): 1 atom ### Step 6: Calculate the Total Number of Atoms Now, we add up the number of atoms: - Total atoms = 1 (C) + 2 (H) + 1 (O) = 4 atoms ### Final Answer The number of atoms present in the empirical formula of acetic acid is **4**. ---

To find the number of atoms present in the empirical formula of acetic acid (CH₃COOH), we will follow these steps: ### Step 1: Identify the Molecular Formula The molecular formula of acetic acid is given as CH₃COOH. ### Step 2: Count the Atoms in the Molecular Formula In the molecular formula CH₃COOH, we can count the number of each type of atom: - Carbon (C): 2 atoms (from CH₃ and COOH) ...
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Molecular formula of acetic acid is CH_(3)COOH . Calculate its percentage composition . [Given : Atomic masses C=12, H = 1 and O = 16].

Molecular formula of acetic acid is CH_(3) COOH. Calculate its percentage composition by mass [ Given the atomic masses, C = 12, H = 1, and O = 16 ]

Knowledge Check

  • The molecular formula of acetic acid (ethanoic acid) is ………… .

    A
    `HCOOH`
    B
    `CH_(3)COOH`
    C
    `C_(2)H_(5)COOH`
    D
    `C_(3)H_(7)COOH`
  • The molecular formula of ethanoic acid is C_(2)H_(4)O_(2) . Its empirical formula is

    A
    `C_(4)H_(8)O_(2)`
    B
    `CH_(2)O`
    C
    `CHO`
    D
    `CHO_(2)`
  • PASSAGE-II : Empirical formula is the simplest formula of the compound which gives the atomic ratio of various elements present in one molecule of the compound. However, the molecular formula of the compound gives the number of atoms of various elements present in one molecule of the compound. Molacular formula = (Empirical formula) xxn implies n=("Molecular mass")/("Empirical formula mass") A compound may have same empirical and molecular formula. Both these formulae are calculated using percentage composition of constituent elements. 10 g of hydrofluoric acid gas occupies 5.6 litre of volume at STP. If the empirical formula of the gas is HF, then its molecular formula in the gaseous state will be

    A
    HF
    B
    `H_(2)F_(2)`
    C
    `H_(3)F_(3)`
    D
    `H_(4)F_(4)`
  • Similar Questions

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    PASSAGE-II : Empirical formula is the simplest formula of the compound which gives the atomic ratio of various elements present in one molecule of the compound. However, the molecular formula of the compound gives the number of atoms of various elements present in one molecule of the compound. Molacular formula = (Empirical formula) xxn implies n=("Molecular mass")/("Empirical formula mass") A compound may have same empirical and molecular formula. Both these formulae are calculated using percentage composition of constituent elements. Which of the following compounds have the same empirical formula as that of formaldehyde?

    Which molecular formula is also an empirical formula?

    The molecular formula of acetic acid (ethanoic acid) is ……………..

    Empirical formula is the simplest formula of the compound which gives the atomic ratio of various elements present in one molecule of the compound. However, the molecular formula of the compound gives the number of atoms of various elements present in one molecule of the compound. Molecular formula=(Empirical formula) xxn n=("Molecular mass")/("Empirical formula mass") A compound may have same empirical and molecular formulae Both these formulae are calculated by using percentage composition of constituent elements. Which of the following compounds have same empirical formula?

    Empirical formula is the simplest formula of the compound which gives the atomic ratio of various elements present in one molecule of the compound. However, the molecular formula of the compound gives the number of atoms of various elements present in one molecule of the compound. Molecular formula=(Empirical formula) xxn n=("Molecular mass")/("Empirical formula mass") A compound may have same empirical and molecular formulae Both these formulae are calculated by using percentage composition of constituent elements. Which of the following represents the formula of a substance which contains 50% oxygen?