A body of mass 2kg is moving on a smooth floor in straight line with a uniform velocity of `10m//s` Resultant force on the body is

Options

A. 20N
B. 10N
C. 2N
D. Zero

Explanation

To solve the problem, we need to determine the resultant force acting on a body of mass 2 kg moving with a uniform velocity of 10 m/s on a smooth floor. Here’s the step-by-step solution:

### Step 1: Understand the Motion
The body is moving with a uniform velocity of 10 m/s. This means that both the speed and direction of the body are constant.

**Hint:** Recall that uniform velocity means no change in speed or direction.

### Step 2: Identify the Acceleration
Since the body is moving with a uniform velocity, there is no change in its velocity. Therefore, the acceleration of the body is zero.

**Hint:** Remember that acceleration is defined as the rate of change of velocity. If velocity is constant, acceleration is zero.

### Step 3: Apply Newton's Second Law of Motion
According to Newton's second law of motion, the resultant force (F_r) acting on an object is given by the formula:
\[ F_r = m \cdot a \]
where:
- \( F_r \) is the resultant force,
- \( m \) is the mass of the body,
- \( a \) is the acceleration.

### Step 4: Substitute the Values
We know:
- Mass \( m = 2 \) kg,
- Acceleration \( a = 0 \) m/s² (from Step 2).

Now substituting these values into the formula:
\[ F_r = 2 \, \text{kg} \cdot 0 \, \text{m/s}^2 = 0 \, \text{N} \]

**Hint:** When multiplying any number by zero, the result is always zero.

### Step 5: Conclusion
The resultant force acting on the body is 0 N.

**Final Answer:** The resultant force on the body is **0 N**.