An object travels 16m in 4s and then another 16m in 3 s. what is the average speed of the object?

Options

A. 4.57 m/s
B. 7.54 m/s
C. 5.74 m/s
D. 4.75 m/s

Explanation

To find the average speed of the object that travels different distances in different time intervals, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the distances and times:**
- The object travels 16 meters in the first interval.
- The time taken for the first interval (T1) is 4 seconds.
- The object travels another 16 meters in the second interval.
- The time taken for the second interval (T2) is 3 seconds.

2. **Calculate the total distance traveled:**
- Total distance (S) = Distance in the first interval (S1) + Distance in the second interval (S2)
- S = S1 + S2 = 16 meters + 16 meters = 32 meters.

3. **Calculate the total time taken:**
- Total time (T) = Time in the first interval (T1) + Time in the second interval (T2)
- T = T1 + T2 = 4 seconds + 3 seconds = 7 seconds.

4. **Calculate the average speed:**
- Average speed = Total distance / Total time
- Average speed = S / T = 32 meters / 7 seconds = 4.57 meters per second.

5. **Final Answer:**
- The average speed of the object is approximately 4.57 m/s.