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The charges on an object is given by Q =...

The charges on an object is given by Q = ne, here n is number of electrons and e is electronic charge `(-1.6 xx 10^(-19) C)`. If an object has charge `-5 xx 10^(-19) C`, what should be number of excess electron on it?

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The correct Answer is:
3
`Here, Q = -5 xx 10^(-19) C, e = - 1.6 xx 10^(-19) C, n = ?`
`:. n = Q/e= (-5 xx 10 ^(-19) C)/(-1.6 xx 10 ^(-19)C)= 3.125=3.`
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Knowledge Check

  • The electronic charge is 1.6xx10^(-19) coulomb. If a body carries a negative charge of 9.6xx10^(-10) coulombs, what is the number of excess electrons on the body?

    A
    `6xx10^(9)`
    B
    `1//6xx10^(-29)`
    C
    `6xx10^(29)`
    D
    `6xx10^(29)`

  • The charge on the electron is 1.6 xx 10^(-19) C . The order of magnitude is

    A
    `10^(19)C`
    B
    `10^(18)m`
    C
    `10^(-18)C`
    D
    `10^(-19)C`

  • An ebonite rod acquires a negative change of 6.4 xx 10^-10 C . The number of excess electrons it has is

    A
    `4 xx 10^9`
    B
    `4 xx 10^(-9)`
    C
    `4 xx 10^(-29)`
    D
    `4 xx 10^(29)`

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