A car moves along a straight path with variable velocity as shown in the figure. When the car is at position A, its velocity is 10 m `s^(-1)` and when it is at position B, its velocity is 20 m `s^(-1)` . If the car take 5 seconds of times to move from A to B, find the acceleration of the car.

Answer

2

Explanation

Initial position of the car at position A = u = 10 m `s^(-1)` Final velocity of the car at position B = v = 20 m `s^(-1)` . The change in velocity of the car `triangle v=v-u=20 ms^(-1) -10 m s^(-1) =10 m s^(-1)` The time taken for the car to move from A to B, `trianglet=5 s`
`therefore` Acceleration of the car,
`a=(trianglev)/(trianglet)=(10 ms^(-1))/(5s)=2 m s^(-2)`