For an isolated system, `Delta U=0`. What will be `DeltaS`?

Options

A. `0`
B. `gt 0`
C. `lt 0`
D. `ge 0`

Explanation

For an isolated system `Delta U =0` and for a spontaneous process, total entropy change must be position Mereover `Delta S = ( q _(rev))/( T) = ( Delta H )/( T) = ( Delta U + p Delta V)/(T) = ( p Delta V)/(T) (therefore Delta U = 0) i.e., T Delta S gt 0`