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The volume of the reaction vessel contai...

The volume of the reaction vessel containing an equilibrium mixture in the reaction,
`SO _(2) CL _(2 (g) )hArr SO _(2 _(g)) + Cl _(2 (g)) ` is increased. When equilibrium is re-established:

A

the amount of `SO_(2(g))` will decrease

B

the amount of `SO_(2)Cl_(2(g))` will increase

C

the amount of `Cl_(2(g))` will increase

D

the amount of `Cl_(2(g))` will remain unchaned

Text Solution

Verified by Experts

The correct Answer is:
C
An increase in volume for the equilibrium having `K_(o) = ([SO_(2)][Cl_(2)])/([SO_(2)Cl_(2)]) = (["mole of "SO_(2)]["mole of " Cl_(2)])/(["mole of " SO_(2)Cl_(2)] xx "volume")` will increase the mole of `Cl_(2)` or `SO_(2)` to maintain `K_(c )` values constant.
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Knowledge Check

  • The vapour density of the equilibrium mixture of the reaction: SO _(2) Cl _(2) (g) hArr SO _(2) (g) + Cl _(2) (g) is 50. The percent dissociation of SO_(2) Cl_(2) is

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    `33.00 `
    B
    `35.0`
    C
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    D
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  • The vapour density of the equilibirum mixture of the reaction : SO_(2)Cl_(2(g)) hArr SO_(2)(g) + Cl_(2)(g) is 50. The percent dissociation of SO_(2)Cl_(2) is

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    `33.00`
    B
    `35.0`
    C
    `30.0`
    D
    `66.00`

  • For a hypothetical reaction : 4A_((g)) + 5B_((g)) hArr 4P_((g)) + 6Q_((g)) . The equilibrium constant K_(c) has units :

    A
    mol `L^(-1)`
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    `mol^(-1)L`
    C
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    D
    unitless

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