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The equilibrium, concentration of H (2),...

The equilibrium, concentration of `H _(2), I _(2), ` and HI are respectively `5. 0 , 3. 0` and `17 mol L ^(-1)` . What will be the value of `K _(c)` for the reaction `H _(2) + I _(2) ` `rarr` `2HI` ?

Text Solution

Verified by Experts

For the reactin , `H_(2)(g) + I_(2)(g) hArr 2HI(g)`
equilibrium constant, `K_(c) = ([HI]^(2))/([H_(2)][I_(2)]) = ((17 mol L^(-1))^(2))/((5.0 mol L^(-1))(3.0 mol L^(-1))) = 19.27`
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Knowledge Check

  • Under what condition the order of the reaction, 2HI rarr H_(2)(g) + I_(2)(g) , is zero

    A
    at high temperature
    B
    at high partial pressure of HI
    C
    at low partial pressure of HI
    D
    at high partial pressure of `H_(2)`

  • For a system, A + 2B hArr C , the equilibrium concentrations are [A] = 0.06, [B] = 0.12 and [C] = 0.216 . The value of K_(c) for the reaction is

    A
    120
    B
    400
    C
    `4 xx 10^(-3)`
    D
    250

  • The following concentration were obtained for the formation of NH_(3)(g) from N_(2)(g) and H_(2)(g) at equilibrium and at 500 K: [N_(2)] = 1 xx 10^(-2)M, [H_(2)] = 2 xx 10^(-2)M and [NH_(3)] = 2xx 10^(-2)M . The equilibrium constant, K_(c) , for the reaction N_(2)(g) + 3H_(2)(g) hArr 2NH_(3)(g) at 500 K is

    A
    `5 xx 10^(3) mol^(-2) dm^(6)`
    B
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    C
    `5 xx 10^(-3) mol^(-2) dm^(6)`
    D
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