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The fourth vertex of a rectangle whose o...

The fourth vertex of a rectangle whose other vertices are (4, 1) (7, 4) and (13, -2) is

A

(10, -5)

B

(10, 5)

C

(-10, 5)

D

(-10, -5)

Text Solution

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The correct Answer is:
To find the fourth vertex of a rectangle given three vertices, we can use the properties of a rectangle where opposite sides are equal and the diagonals bisect each other. The three given vertices are A(4, 1), B(7, 4), and C(13, -2). We will denote the fourth vertex as D(x, y). ### Step-by-Step Solution: 1. **Identify the Given Points**: The vertices of the rectangle are A(4, 1), B(7, 4), and C(13, -2). We need to find the coordinates of the fourth vertex D(x, y). 2. **Use the Midpoint Formula**: The diagonals of a rectangle bisect each other. Therefore, the midpoint of diagonal AC should equal the midpoint of diagonal BD. - Midpoint of AC = \(\left(\frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2}\right)\) - Midpoint of BD = \(\left(\frac{x_3 + x_4}{2}, \frac{y_3 + y_4}{2}\right)\) Let's calculate the midpoint of AC: - A(4, 1) and C(13, -2) - Midpoint of AC = \(\left(\frac{4 + 13}{2}, \frac{1 + (-2)}{2}\right) = \left(\frac{17}{2}, \frac{-1}{2}\right)\) 3. **Set Up the Equation for Midpoint of BD**: Let D be (x, y). The coordinates of B are (7, 4). - Midpoint of BD = \(\left(\frac{7 + x}{2}, \frac{4 + y}{2}\right)\) Setting the midpoints equal: \[ \frac{7 + x}{2} = \frac{17}{2} \quad \text{and} \quad \frac{4 + y}{2} = \frac{-1}{2} \] 4. **Solve for x**: From the first equation: \[ 7 + x = 17 \implies x = 17 - 7 = 10 \] 5. **Solve for y**: From the second equation: \[ 4 + y = -1 \implies y = -1 - 4 = -5 \] 6. **Conclusion**: The coordinates of the fourth vertex D are (10, -5). ### Final Answer: The fourth vertex of the rectangle is D(10, -5).
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Knowledge Check

  • The third vertex of a triangle, whose two vertices are (-4,1) and (0, -3) and centroid is at the origin is

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    (3, 1)
    B
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  • The fourth vertex D of a parallelogram ABCD whose three vertices are A(-2,3), B(6,7) and C(8,3) is

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    `(0,1)`
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    `(0,-1)`
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    `(-1,0)`
    D
    `(1,0)`
  • The co-ordinates of the third vertex of an equilateral triangle whose two vertices are at (3,4) and (-2,3) are

    A
    (1,1) or (1,-1)
    B
    `((1+sqrt(3))/2,(7-5sqrt(3))/2)` or `((1-sqrt(3))/2,(7+5sqrt(3))/2)`
    C
    `(-sqrt(3),sqrt(3))` or `(sqrt(3),sqrt(3))`
    D
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