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The equation of the line which bisects t...

The equation of the line which bisects the obtuse angle between the lines x - 2y + 4 = 0 and 4x - 3y + 2 = 0, is

A

(4 - 5 ) x - (3 - 2 5 )y + (2 - 4 5 ) = 0

B

(4 + 5 ) x + (3 + 2 5 ) y + (2 + 4 5 ) = 0

C

(4 + 5 ) x - (3 + 2 5 ) y + (2 + 4 5 ) = 0

D

None of these

Text Solution

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The correct Answer is:
To find the equation of the line that bisects the obtuse angle between the two given lines \(x - 2y + 4 = 0\) and \(4x - 3y + 2 = 0\), we can follow these steps: ### Step 1: Identify the coefficients of the lines The equations of the lines are: 1. \(L_1: x - 2y + 4 = 0\) 2. \(L_2: 4x - 3y + 2 = 0\) From these equations, we can identify: - For \(L_1\): \(A_1 = 1\), \(B_1 = -2\), \(C_1 = 4\) - For \(L_2\): \(A_2 = 4\), \(B_2 = -3\), \(C_2 = 2\) ### Step 2: Calculate the angle bisector formula The angle bisectors of two lines can be found using the formula: \[ \frac{A_1x + B_1y + C_1}{\sqrt{A_1^2 + B_1^2}} = \pm \frac{A_2x + B_2y + C_2}{\sqrt{A_2^2 + B_2^2}} \] ### Step 3: Calculate the left-hand side for both lines For \(L_1\): \[ \sqrt{A_1^2 + B_1^2} = \sqrt{1^2 + (-2)^2} = \sqrt{1 + 4} = \sqrt{5} \] Thus, the left-hand side becomes: \[ \frac{1 \cdot x - 2 \cdot y + 4}{\sqrt{5}} = \frac{x - 2y + 4}{\sqrt{5}} \] For \(L_2\): \[ \sqrt{A_2^2 + B_2^2} = \sqrt{4^2 + (-3)^2} = \sqrt{16 + 9} = \sqrt{25} = 5 \] Thus, the right-hand side becomes: \[ \frac{4 \cdot x - 3 \cdot y + 2}{5} \] ### Step 4: Set up the equation for the obtuse angle bisector Since we want the obtuse angle bisector, we take the positive sign in the equation: \[ \frac{x - 2y + 4}{\sqrt{5}} = \frac{4x - 3y + 2}{5} \] ### Step 5: Cross-multiply to eliminate the fractions Cross-multiplying gives: \[ 5(x - 2y + 4) = \sqrt{5}(4x - 3y + 2) \] ### Step 6: Expand both sides Expanding the left-hand side: \[ 5x - 10y + 20 \] Expanding the right-hand side: \[ 4\sqrt{5}x - 3\sqrt{5}y + 2\sqrt{5} \] ### Step 7: Rearranging the equation Setting both sides equal gives: \[ 5x - 10y + 20 = 4\sqrt{5}x - 3\sqrt{5}y + 2\sqrt{5} \] Rearranging terms leads to: \[ 5x - 4\sqrt{5}x + 3\sqrt{5}y - 10y + 20 - 2\sqrt{5} = 0 \] ### Step 8: Combine like terms Combining like terms yields: \[ (5 - 4\sqrt{5})x + (3\sqrt{5} - 10)y + (20 - 2\sqrt{5}) = 0 \] ### Final Step: Simplify the equation This represents the equation of the line that bisects the obtuse angle between the two given lines.
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The equation of the line which bisects the obtuse angle between the line x-2y+4=0 and 4x-3y+2=0 is

The equaiton of the line which bisects the obtuse angle between the lines x-2y+4=0 and 4x-3y+2=0 (A) (4-sqrt(5))x-(3-2(sqrt(5)) y+ (2-4sqrt(5))=0 (B) (3-2sqrt(5)) x- (4-sqrt(5))y+ (2+4(sqrt(5))=0 (C) (4+sqrt(5)x-(3+2(sqrt(5))y+ (2+4(sqrt(5))=0 (D) none of these

Knowledge Check

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