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The set (A-B) cup (B-A) is equal to...

The set `(A-B) cup (B-A)` is equal to

A

`[A-(A cap B] cap [B -(A cap B)]`

B

`(Auu B)-(A nn B)`

C

`A-(A cap B)`

D

`bar(A cap B) - A cup B`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to find the value of the set \( (A - B) \cup (B - A) \). ### Step-by-Step Solution: 1. **Define the Sets**: Let's assume: - Set \( A = \{1, 2\} \) - Set \( B = \{2, 3\} \) 2. **Calculate \( A - B \)**: - \( A - B \) means we take the elements in \( A \) that are not in \( B \). - From \( A = \{1, 2\} \) and \( B = \{2, 3\} \), we see that \( 2 \) is in both sets. - Therefore, \( A - B = \{1\} \). 3. **Calculate \( B - A \)**: - \( B - A \) means we take the elements in \( B \) that are not in \( A \). - From \( B = \{2, 3\} \) and \( A = \{1, 2\} \), we see that \( 2 \) is in both sets. - Therefore, \( B - A = \{3\} \). 4. **Combine the Results**: - Now we need to find the union of the two sets: \( (A - B) \cup (B - A) \). - We have \( A - B = \{1\} \) and \( B - A = \{3\} \). - Thus, \( (A - B) \cup (B - A) = \{1\} \cup \{3\} = \{1, 3\} \). 5. **Conclusion**: - The final result is \( (A - B) \cup (B - A) = \{1, 3\} \).
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Knowledge Check

  • If A, B and C are non-empty sets, then (A - B) cup (B - A) is equal to

    A
    `( A cup B) - B`
    B
    `A - ( A cap B)`
    C
    `( A cup B) - ( A cap B)`
    D
    `( A cap B) - ( A cup B)`
  • For two sets A and B, A cup (B-A) is equal to-

    A
    A
    B
    B
    C
    `phi`
    D
    `(A cup B)`
  • For any two sets A and B, the value of [(A-B) cup B] is equal to

    A
    `A cap B`
    B
    `A cap B`
    C
    A-B
    D
    B-A
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