Three particles of masses 1.0 kg 2.0 kg and 3.0 kg are placed at the corners A,B and C respectively of an equilateral triangle ABC of edge 1m. Locate the centre of mass of the system.

Explanation

`m_1=1kg, `
`m_2=2kg`
`m_3=3g`

`x_1=0,`
`x_2=1, x_3=1/2`
`y_1=0, y_2=0, y_3=sqrt3/2`
the position of centre of mass is
`C.M.=(m_1x_1+m_2x_2+m_3x_3)/(m_1+m_2+m_3)`
((1xx0)+(2x1)+(3xx1/2)/(1+2+3)`
((1xx0)+(2xx0)+(sqrt3/2))/(1+2+3)`
`(7/12,sqrt3/4)` from the point B.