Home
Class 11
PHYSICS
Water is filled in a flask up to a heigh...

Water is filled in a flask up to a height of 20 cm. The bottom of the flask is circular with radius 10 cm. If the atmospheric pressure is `1.01xx10^5` Pa, find the force exerted by the water on the bottom. Take `g=10 ms^-2` and density of water =1000 kgm^-3.

Text Solution

Verified by Experts

The pressure at te surface of the wter is equal to the atmospheric pressure `P_0`. The pressure at the bottom is
`P=P_0+hrhog`
`=1.01xx10^5Pa+(0.20m)(1000kgm^-3)(10ms^i-2)`
`=1.0xx10^5Pa+0.02x10^5Pa`
`=1.03xx10^5Pa`.
the area of the bottom `=pi r^2=3.14xx(0.1m)^-2`
`=0.0314m^2`
The force on the bottom therefore
`=F=Ppir^2`
`=(1.03xx10^5Pa)xx(0.0314m^2)=3230N`
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

Similar Questions

Explore conceptually related problems

A beaker of circular cross-section of radius 4 cm is filled with mercury up to a height of 10 cm. Find the force exerted by the mercury on the bottom of the beaker. The atmospheric pressure =10^5Nm^-2 . Density of mercury =13600 kgm^-3. Take g10ms^-2

A glass full of water has a bottom of area 20 cm^(2) , top of area 20 cm , height 20 cm and volume half a litre. Find the force exerted by the water on the bottom. Atmospheric pressure = 1.0 xx 10^(5) N//m^(2) . Density of water = 1000 kg//m^(-3) and g = 10 m//s^(2)

A capillary tube of radius 0.20 mm is dipped vertically in water. Find the height of the water column raised in the tube. Surface tension of water =0.075Nm^-1 and density of water =1000 kgm^-3. Take g=10 ms^-2 .

An air bubble of radius 2.0mm is formed at the bottom of a 3.3m deep river. Calculate the radius of the bubble as it comes to the surface. Atmospheric pressure =1.0xx10^(5)Pa and desnity of water =1000kg m^(-3).

Find the mass of silver of volume 50 cm^3 and density 10.5g//cm^3 .

Water leaks out from an open tank through a hole of area 2mm^2 in the bottom. Suppose water is filled up to a height of 80 cm and the area of cross section of the tankis 0.4 m^2 . The pressure at the open surface and the hole are equal to the atmospheric pressure. Neglect the small velocity of the water near the open surface in the tank. a. Find the initial speed of water coming out of the hole. b. Findteh speed of water coming out when half of water has leaked out. c. Find the volume of water leaked out during a time interval dt after the height remained is h. Thus find the decrease in height dh in term of h and dt. d. From the result of part c. find the time required for half of the water to leak out.

An electorn moves in a circle of radius 10cm with a constant speed of 4.0xx10^(6)ms^(-1) .Find the electric current at a point on the circle.

The heights of mercury surfaces in the two arms of the manometer shown in figure are 2 cm and 8cm. Atmospheric pressure =1.01xx10^5Nm^-2 . Find (a). the pressure of the gas in the cylinder and (b). the pressure of mercury at the bottom of the U tube.

Oxygen is filled in a closed metal jar of volume 1.0xx10^(-3)m^(3) at a pressure of 1.5xx10^(5)Pa. and temperature 400K.The jar has a small leak in it. The atmospheric pressure is 1.0xx10^(5) Pa and the atmospheric temperature is 300K. Find the mass of the gas that leaks out by time the pressure and the temperature inside the jar equlise with the surrounding.

Find the terminal velocity of a rain drop of radius 0.01 mm. The coefficient of viscosity of air is 1.8xx10^-5 N-sm^-2 and its density is 1.2kgm^-3 .Density of water =1000kgm^-3 . Take g=10ms^-2