When `1.0 xx 10^12`electrons are transferred from one conductor to another, a potential difference of `10 V` . What will be capacitance of the two -conductor system .

Explanation

Given that :
Number of elctron `= 1 xx 10^(12)`,
Net charge `Q= 1 xx 10^(12) xx 1.6 xx 10^(-19)`
The net potential difference `= 10 V`
So, `C = 1.6 xx 10^(7) / 10 = 1.6 xx 10^(-8) F`