The bohr radius is given by `a_(0) = (epsilon_(0)h^(2))/(pi m e^(2))` verify that the RHS has dimesions of length

Answer

A

Explanation

`a= (in_0h^2)/(pime^2) = (A^2T^2(ML^2T^-1))/(M^2L^3T^-2) = L`
`=(M^2L^2T^-2)/(M^2L^3T^-2) = L`
Clearly `a_0` has dimensions of length.