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By passage of 1 F electricity...

By passage of 1 F electricity

A

1 mole of Cu is deposited

B

0 . 5 mole of Mg is deposited

C

9 g of Al is deposited

D

`5 . 6 L` of `O_(2)` gas is evolved at the anode

Text Solution

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The correct Answer is:
(B) , ( C ) , AND ( D )
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Knowledge Check

  • By passage of 1 F of electricity:

    A
    1 mol of Cu is deposited
    B
    0.5 mol of Mg iĊŸ deposited
    C
    5.6 L of `O_2` gas evolved at anode
    D
    9 g of Al is deposited

  • By passage of 1 F of electricity, which is not obtained?

    A
    1 mol of Cu
    B
    `0.5` mol of Mg
    C
    9 g of Al
    D
    `5.6` l of `O_(2)` gas at anode

  • By passage of 1 F of electricity, which is not obtained?

    A
    1 mol of Cu
    B
    `0.5` mol of Mg
    C
    9 g of Al
    D
    `5.6l` of `O_(2)` gas at anode

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    The passage of electricity in the Daniell cell when Zn and Cu electrodes are connected is from :

    On passing 0.1 F of electricity through aluminimum chloride, the amount of aluminimu metal deposited on cathode is (A1 =27) .

    1 C electricity deposits

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