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There is a liquid of mass m and specific...

There is a liquid of mass m and specific heat capacity c and temperature T. Another liquid of mass `m/2` and specific heat 2C is heated to a temperature 2T. If these two liquids are mixed, the resulting temperature of the mixture is (assume no change in the state of liquids)

A

`(2/3)^T`

B

`(8/5)^T`

C

`(3/5)^T`

D

`(3/2)^T`

Text Solution

Verified by Experts

The correct Answer is:
D
Let T be the final temperature of the mixture. Then, Heat gained =Heat lost
`mc(T. – T) =m/2 (2c) (2T - T.)`
`T. = 3/2T`
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Knowledge Check

  • A liquid of mass m and specific heat c is heated to a temperature 2T. Another liquid of mass m/2 and specific heat 2 c is heated to a temperature T. If these two liquids are mixed, the resulting temperature of the mixture is

    A
    `(2//3)T`
    B
    `(8//5)T`
    C
    `(3//5)T`
    D
    `(3//2)T`

  • A liquid of mass M and specific heat S is at a temperature 2T . Another liquid of thermal capacity 1.5 times the first liquid at a temperature (T)/(3) is added to it. The resultant temperature of the mixture will be

    A
    `(2T)/(3)`
    B
    `(T)/(2)`
    C
    `T`
    D
    `(4T)/(3)`

  • When a hot liquid is mixed with a cold liquid, the temperature of the mixture

    A
    first decreases then becomes constant
    B
    first increases then becomes constant
    C
    continously increases
    D
    is undefined for some time and then becomes nearly constant

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