There is a liquid of mass m and specific heat capacity c and temperature T. Another liquid of mass `m/2` and specific heat 2C is heated to a temperature 2T. If these two liquids are mixed, the resulting temperature of the mixture is (assume no change in the state of liquids)

Options

A. `(2/3)^T`
B. `(8/5)^T`
C. `(3/5)^T`
D. `(3/2)^T`

Answer

D

Explanation

Let T be the final temperature of the mixture. Then, Heat gained =Heat lost
`mc(T. – T) =m/2 (2c) (2T - T.)`
`T. = 3/2T`