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Find the equation of the circle which pa...

Find the equation of the circle which passes through the origin and intersects the circles below, orthogonally.
`x^2 + y^2 - 4x + 6y + 10 = 0 `.
`x^2 + y^2 + 12y + 6 = 0 . `

Answer

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Find the equation of the circle which passes through the origin and intersects the circles below, orthogonally. x^2 + y^2 - 4x - 6y - 3 = 0 . x^2 + y^2 - 8y + 12 = 0 .

Find the equation of the circle which passes through the origin and intersects each of the following circles orthogonally. x^2+y^2-4x+6y+10=0 x^2+y^2+12y+6=0

Knowledge Check

  • The equation of the circle which passes through the origin has its centre on the line x+y=4 and cuts orthogonally the circle x^2+y^2-4x+2y+4=0

    A
    `x^2+y^2-4x-4y=0`
    B
    `x^2+y^2-2x-6y=0`
    C
    `x^2+y^2-6x-2y=0`
    D
    `x^2+y^2+4x-12y=0`

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