An organic compound A on heating with concentrated `H_(2)SO_(4)` gave product B and on warming with alkaline `KMnO_(4)` gave compound C. Compound A on heating with compound C in presence of concentrated `H_(2)SO_(4)` formed Compound D, which has fruity smell, Identify the compounds A,B,C and D :

Options

A. A = Alcohol, B = Carboxylic acid,
C = Alkent, D = Ester,
B. A = Carboxylic acid, B = Ester,
C = Alkene , D = Alcohol.
C. A = Alcohol, B = Alkene,
C = Carboxylic acid, D = Ester.
D. A = Alkene, B = Alcohol, C = Ester,
D = Carbocxylic acid.

Explanation

To solve the problem, we need to identify the organic compounds A, B, C, and D based on the reactions described. Let's break down the steps:

### Step 1: Identify Compound A
The problem states that compound A reacts with concentrated sulfuric acid (H₂SO₄) to yield compound B. Since concentrated H₂SO₄ is a dehydrating agent, it suggests that compound A is likely an alcohol. A common alcohol that can undergo dehydration is ethanol (C₂H₅OH).

### Step 2: Reaction of Compound A with H₂SO₄
When ethanol (A) is heated with concentrated H₂SO₄, it undergoes dehydration to form an alkene. The reaction can be represented as follows:
\[ \text{C}_2\text{H}_5\text{OH} \xrightarrow{\text{H}_2\text{SO}_4} \text{C}_2\text{H}_4 + \text{H}_2\text{O} \]
Thus, compound B is ethene (C₂H₄).

### Step 3: Reaction of Compound A with Alkaline KMnO₄
Next, compound A (ethanol) is warmed with alkaline potassium permanganate (KMnO₄), which is a strong oxidizing agent. This reaction will oxidize ethanol to acetic acid (C₂H₄O₂):
\[ \text{C}_2\text{H}_5\text{OH} + \text{[O]} \rightarrow \text{C}_2\text{H}_4\text{O}_2 \]
Thus, compound C is acetic acid (C₂H₄O₂).

### Step 4: Reaction of Compounds C and A to form Compound D
Now we need to consider the reaction of compound A (ethanol) and compound C (acetic acid) in the presence of concentrated H₂SO₄. This reaction is an esterification reaction, which produces an ester:
\[ \text{C}_2\text{H}_5\text{OH} + \text{C}_2\text{H}_4\text{O}_2 \xrightarrow{\text{H}_2\text{SO}_4} \text{C}_2\text{H}_5\text{OOC}\text{C}_2\text{H}_5 + \text{H}_2\text{O} \]
The product of this reaction is ethyl acetate (C₄H₈O₂), which is known for its fruity smell. Thus, compound D is ethyl acetate (C₄H₈O₂).

### Summary of Compounds
- **Compound A**: Ethanol (C₂H₅OH)
- **Compound B**: Ethene (C₂H₄)
- **Compound C**: Acetic acid (C₂H₄O₂)
- **Compound D**: Ethyl acetate (C₄H₈O₂)