Home
Class 12
PHYSICS
If the source of light used in a Young's...

If the source of light used in a Young's Double Slit experiment is changed from red to blue, then

A

the fringes will become brighter

B

consecutive fringes will come closer

C

the number of maxima formed on the screen increases

D

the central bright fringe will become a dark fringe.

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to analyze the effects of changing the light source in a Young's Double Slit Experiment from red light to blue light. ### Step-by-Step Solution: 1. **Understanding Wavelength Change**: - Red light has a longer wavelength compared to blue light. When we change the source from red to blue, the wavelength (λ) decreases. - **Hint**: Remember that the visible spectrum ranges from red (longer wavelength) to blue (shorter wavelength). 2. **Fringe Width Calculation**: - The fringe width (β) in a Young's Double Slit Experiment is given by the formula: \[ \beta = \frac{\lambda D}{d} \] where: - \( \lambda \) = wavelength of light - \( D \) = distance from the slits to the screen - \( d \) = distance between the slits. - Since \( \lambda \) decreases when changing from red to blue, the fringe width \( \beta \) will also decrease. - **Hint**: A smaller wavelength results in a smaller fringe width. 3. **Effect on Consecutive Fringes**: - As the fringe width decreases, the distance between consecutive bright or dark fringes also decreases. This means that the fringes will come closer together. - **Hint**: Think about how the spacing between the fringes is affected by the wavelength. 4. **Number of Maxima**: - The number of maxima (bright fringes) that can fit on the screen increases as the fringe width decreases. This is because with smaller fringe width, more fringes can fit within the same distance on the screen. - **Hint**: More closely spaced fringes mean that more of them can fit in the same length. 5. **Conclusion**: - Therefore, the correct options are: - The consecutive fringes will come closer (Option B). - The number of maxima formed on the screen increases (Option C). ### Final Answer: The correct options are B and C: - The consecutive fringes will come closer. - The number of maxima formed on the screen increases.
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • WAVE OPTICS

    AAKASH SERIES|Exercise LECTURE SHEET (EXERCISE - I) (INTERFERENCE & YDSE) Level - II (ADVANCED) Linked Comprehension type questions|6 Videos
  • WAVE OPTICS

    AAKASH SERIES|Exercise LECTURE SHEET (EXERCISE - I) (INTERFERENCE & YDSE) Level - II (ADVANCED) Matrix Match Type Questions|2 Videos
  • WAVE OPTICS

    AAKASH SERIES|Exercise LECTURE SHEET (EXERCISE - I) (INTERFERENCE & YDSE) Level - II (ADVANCED) (straight objective Type Questions)|31 Videos
  • WAVE MOTION AND SOUND

    AAKASH SERIES|Exercise PROBLEMS (LEVEL - II)|97 Videos
  • WAVES

    AAKASH SERIES|Exercise EXERCISE-III (Doppler effect :)|15 Videos

Similar Questions

Explore conceptually related problems

If the source of light used in a young's double slit experiment is changed from red to violet

In Young's double slit experiment:

A Young's double slit experiment is performed with white light, then

If young's double slit experiment is performed in water

A Young's double slit experiment is performed with white light.

When we close one slit in the Young's double slit experiment then

If the width of the slit S in Young's double slit experiment is gradually increased

What happens by the use of white light in Young's double slit experiment:

The intensity of the light coming from one of the slits in a Young's double slit experiment is double the intensity from the other slit. Find the ratio of the maximum intensity to the minimum intensity in the interference fringe pattern observed.

The width of one of the two slits in a Young's double slit experiment is double of the other slit. Assuming that the amplitude of the light coming from a slit is proportional to the slit width, find the ratio of the maximum to the minimum intensity in the interference pattern.