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The energy of a photon of sodium ligh...

The energy of a photon of sodium light `( lamda = 589 nm)` equal to the band gap of a semiconducing material . Find the minimum energy E required to create a hole -electron pair.

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To solve the problem of finding the minimum energy \( E \) required to create a hole-electron pair in a semiconductor material, given that the energy of a photon of sodium light (with a wavelength of \( \lambda = 589 \, \text{nm} \)) is equal to the band gap energy of the semiconductor, we can follow these steps: ### Step 1: Understand the relationship between energy and wavelength The energy of a photon can be calculated using the formula: \[ E = \frac{hc}{\lambda} \] where: ...
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The energy of a photon of sodium light (lambda=589 nm) equal the band gap of a semiconducting material.(a)Find the minimum energy E requried to create a hole-electron pair.(b)Find the value of E//kT at a temperature of 300K.

The binding energy of an electron in the gorund state of He atom is equal to E_0 = 24.6 eV. Find the energy required to remove both electrons form the atom.

Knowledge Check

  • If the energy of a photon of sodium light ( lambda =589 nm) equals the band gap of semiconductor, the minimum energy required to create hole electron pair

    A
    1.1 eV
    B
    2.1 eV
    C
    3.2 eV
    D
    1.5 eV
  • The binding energy of the electron in the ground state of He atom is equal to E_(0)=24.6 eV . Find the energy required to remove both the electrons from the atom.

    A
    49.2eV
    B
    54.4eV
    C
    79eV
    D
    108.8eV
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