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The electrolysis of a solution resulted ...

The electrolysis of a solution resulted in the formation of `H_2`(g) at cathode and oxygen gas anode. The solution is :

A

AgCl(aq)

B

`H_2SO_4(aq)`

C

highly concentrated NaCl(aq) solution

D

`CuCl_2(aq)`

Text Solution

Verified by Experts

The correct Answer is:
B
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During the electrolysis of a concentrated brine solution. Calculate the moles of chlorine gas produced by the passage of 4F electricity.

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Knowledge Check

  • Electrolysis of aq solution of brine gives

    A
    `Cl_(2)`
    B
    `H_(2)`
    C
    NaBr
    D
    KI

  • Compound A is prepared by the electrolysis of aqueous solution of B using castner- Kellner cell with mercury as cathode and carbon as anode. A and B respecitvely are

    A
    NaOH, NaCl
    B
    NaCl, NaOH
    C
    `NaHCO_(3)` , NaOH
    D
    `Na_(2)CO_(3), NH_(3)`

  • Electrolysis is the process in which electrical energy is converted to chemical energy. In electrolyte cell, oxidation takes place at anode and reduction at cathode. Electrode process depends on the electrode taken for electrolysis. Amount of substance liberated at an electrode is directly proportionation to the amount of charge passed through it. The mass of substance liberated at electrode is calculate using the following realation : m=(itE)/(96500) Here, E represent the equivalent mass and 96500 C is called the faraday constant. Faraday (96500 C) is the charge of 1 mole electron i.e., 6.023 xx 10^(23) electrons, it is used to liberate on gram equivalent of the substance. The passage of current liberates H_2 at cathode and Cl_2 at anode. The solution is

    A
    copper chloride in water
    B
    NaCl in water
    C
    mercuric chloride in water
    D
    `AuCl_3` in water

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