Find the vapour pressure of solution where 0.5 g pf a nonk volatile solute (Mol wt. =65g) is dissolve in 100mL `"CC"l_(4)`.
Given
Density of `"CC"l_(4)=1.58g//cm^(3)`
Vapour pressure of `"CC"l_(4)` at `25^(@)C` is 143 mm Hg.

Answer

`142`

Explanation

Mass of `"CC"l_(4)(W)="Volume"xx"density"`
`=100xx1.58=158g`
Mass of solute (w) =0.5g
`P_(0)=143mmHg,P_(s)=?`
As we know `(P_(0)-P_(s))/(P_(0))=(wxxM)/(mxxW)`
`(143-P_(s))/143=(0.5xx154)/(65xx158)`
`143-P_(S)=(0.5xx154xx143)/(65xx158)`
`143-P_(s)=1.072`
`P_(s)=143-1.072=141.927 mmHg`