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An electron is in 4f orbital. What possi...

An electron is in 4f orbital. What possible values for quantum numbers, n,l,m and s can it have ?

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Since the electron is in a 4f orbital, the value of the principle quantum number, n = 4
For the f-orbital, the secondary quantum number, l = 3
The values of the magnetic quantum (m) are `-l " to " +l` including zero. Therefore, when l = 3, m has seven values, i.e., `-3, -2, -1, 0, +1, +2, and 3`
For each value of m, the spin quantum number, s has two values, i.e., `s = +1//2 and s = -1//2`
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Knowledge Check

  • The total number of orbitals possible for the quantum number n is

    A
    n
    B
    `n^(2)`
    C
    2n
    D
    `2n^(2)`
  • the highest probability of finding the electron in an orbital having values of quantum hnumbers n=3 l=1 and m=1.

    A
    in between any two axis out of three
    B
    On any two axis simultaneously ,perpendicular to each other
    C
    On any one axis out of the three at a time
    D
    on all the three axis simultaneously at a time
  • Assertion : The maximum number of electrons in the shell with principle quantum number n is equal to 2n^(2) . Reason : Two electrons can have the same value of three quantum numbers n, l and m_(l) , but must have the opposite spin quantum number.

    A
    If both assertion and reason are true and reason is the correct explanation of assertion.
    B
    If both assertion and reason are true but reason is not the correct explanation of assertion.
    C
    If assertion is true but reason is false.
    D
    If both assertion and reason are false.
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