50mL of 0.10 B `Ba(OH)_(2)` is added to 50 mLof `0.10 M H_(2)SO_(4)`. The rise in temperature is`DeltaT_(1)` . If experiment is replaced by taking 100 mL of each solution, the rise in temperature is`DeltaT_92)`. Then
A
`DeltaT_(1)= 2DeltaT_(1)`
B
`DeltaT_(2)= 2DeltaT_(1)`
C
`DeltaT_(2)= DeltaT_(1)`
D
`DeltaT_(2)= 4DeltaT_(1)`
Text Solution
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The correct Answer is:
C
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