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Electromagnetic radiation of wavelength 242 nm is just sufficient to ionise the sodium atom . Calculate the ionisation energy of sodium in kJ `mol^(-1)`.

Text Solution

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`E = N hv = Nh (c)/(lamda) = ((6.02 xx 10^(23) mol^(-1)) xx (6.626 xx 10^(-34) Js) xx (3 xx 10^(8) ms^(-1)))/(242 xx 10^(-9) m)`
`= 4.945 xx 10^(5) J mol^(-1) = 494.5 kJ mol^(-1)`
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Knowledge Check

  • An Electro magnetic radiation of wavelength 484 nm is just sufficient of ionise a sodium atom. Calculate the ionisation energy of sodium in kJ/mo, approximately?

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